Category: Updates

Expand $\frac{1}{z-i}$

Expand $\frac{1}{z-i}$ to power series around $z_0=1$ and find the radius of convergence $$\frac{1}{z-i}=\frac{1}{(z-1)+1-i}=\frac{1}{1-i}\cdot\frac{1}{1+...