I have some difficulty with showing that the sequence $$ a_n = \frac{\ln(n)}{n^{1/n}} $$ is divergent. Can anyone help me out with this? Thanks!
$\endgroup$ 11 Answer
$\begingroup$First we can observe that $n^{1/n}\to1$. In fact $n^{1/n}=e^{\frac{\ln(n)}{n}}$ and $\frac{\ln(n)}{n}\to0$.
Therefore the denominator tends to $1$ while the numerator tends to $+\infty$.
$\endgroup$ 2