I have this equation:
$$f(x)=\tan(x)$$
I found the vertical asymptotes to be:
$$x=\frac{\pi}{2}k$$
What is the proper notation for that k is equal to every odd number integer(negative,positive, and zero)?
$$k\in\mathbb{Z}$$ is for every integer, but is there such a symbol for every odd number integer?
Natural numbers are positive, and sometimes zero counting numbers, my question is about integers not natural numbers.
$\endgroup$ 116 Answers
$\begingroup$they are $$(2k+1)\cdot \frac{\pi}{2}$$ with $$k \in \mathbb{Z}$$
$\endgroup$ 4 $\begingroup$You can go with $2\mathbb Z +1$
$\endgroup$ 8 $\begingroup$As long as we're considering alternatives, you could always write $$k\equiv 1\pmod 2$$
$\endgroup$ $\begingroup$Usually people write:
$$\frac{\pi}{2}(2k+1), k \in \mathbb{Z}$$
Sometimes people would use $\mathbb{O}$ for the set of all odd integers, but because it is not so standard they will tell you ahead of time:
$$\mathbb{O}=\{ 2n+1 : n \in \mathbb{Z}\}$$
So then, after defining $\mathbb{O}$, you would say:
$$\frac{\pi}{2}k, k \in \mathbb{O}$$
Get used the $\in$, it simply means "is a member of" some set.
$\endgroup$ 8 $\begingroup$Alternatively, you could write
$$x = \frac{\pi}{2}k \quad , \quad k = \pm1, \pm3, \pm5 \dots$$
$\endgroup$ $\begingroup$You could do $x \epsilon \pi \mathbb{Z} / 2 \pi \mathbb{Z}$, without resorting to $k$.
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