In an event, $P(A)=0.6$, $P(B)=0.2$, $P(A ∩ B)=0.1$. what is the probability of not occurring either A or B.
I am facing problem with the language. I don't understand what "not occurring either A or B" means. I assumed it is "not occurring event A or event B", and solved as follows-
P(not A or not B) = $1- P(AUB)$ = $1-(0.6+0.2-0.1)$ = 0.3
Is it correct?
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$\begingroup$I am facing problem with the language. I don't understand what "not occurring either A or B" means
Yes, it is awkward wording, but does seem to intend to say "neither A nor B occurring."
Which is $(A\cup B)^\complement$, making you calculations correct.
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