My graph is always negative though, and that doesn't make sense cause $t$ is supposed to be positive. I substituted $x$ as $y$ and $t$ as $x$.
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$\begingroup$To draw this graph without the use of a graphics calculator or graphing software, first sketch the graphs of $x=e^{-t}$ and the reflection of this in the $t$ axis, $x=-e^{-t}$
Now sketch the graph of $x=\sin t$ so that it has the same roots as usual, but the amplitude decreases so that it fits between the two exponential graphs, only touching them when $\sin t=\pm1$.
Note that the stationary points are not the same points as where the diminishing sine wave and its exponential "envelopes" touch.
$\endgroup$ $\begingroup$Here are some portions of the graphs:
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