Where does the factor $(y^2 + 1)$ come from?

$\begingroup$

I keep looking and writing out the problem, but I don't know where $(y^2 + 1)$ comes from. I get $y^2(y-3)$ as the numerator instead, but I can't tell if I'm having a brain fart and am missing something.

enter image description here

$\endgroup$ 3

1 Answer

$\begingroup$

$$y^2(y-3)+(y-3)=y^2(y-3)+(1)(y-3)=(y^2+1)(y-3)$$

We just factorize $y-3$ out.

$\endgroup$ 1

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

You Might Also Like