Write an equation for a rational function with:
Vertical asymptotes at $x = -5$ and $x = 5$
$x$ intercepts at $x = -2$ and $x = -6$
Horizontal asymptote at $y = 6$
$y =$ ?
I have $$\frac{(x+2)(x+6)}{(x+5)(x-5)}$$
I know the horizontal asymptote is the division of the highest degree of numerator and denominator. How do I find what it is? $\frac{12x^2}{2x^2} = 6$ ?
$\endgroup$ 01 Answer
$\begingroup$why not just try $f(x)=\frac{6(x+2)(x+6)}{(x+5)(x-5)}$ ?
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